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Math 20F Linear Algebra Lecture 19 1 ✬ ✩ Determinants (Sec. 3.2) Slide 1 • Review: Definition of determinant of n×n matrices. • Properties of determinants. • Determinants and elementary row operations. • Determinant of a product of matrices. ✫ ✪ ✬ ✩ Review: Definition of determinant Definition 1 The determinant of an n×n matrix A = [aij is Slide 2 given by n det(A) = X(−1)1+jdet(A1j)a1j. j=1 This formula is called “expansion by the first row.” ✫ ✪ Math 20F Linear Algebra Lecture 19 2 ✬ ✩ Properties Theorem 1 (Main properties of n×n determinants) Let A=[a1,···,an] be an n×n matrix. Let c be an n-vector. • det([a1,···,aj +c,···,an]) = det([a1,···,aj ···,an]) +det([a1,···,c,···,an]). Slide 3 • det([a1,···,caj,···,an]) = cdet([a1,···,aj,···,an]). • det([a1,···,ai,···,aj,···,an]) = −det([a1,···,aj,···,ai,···,an]). • det([a1,···,ai,···,ai,···,an]) = 0. • det(A) = det(AT). • {a1,···,an} are l.d. ⇔ det([a1,···,an]) = 0. • A is invertible ⇔ det(A) 6= 0. ✫ ✪ ✬ ✩ Properties The properties of the determinant on the column vectors of A and the property det(A) = det(AT) imply the following results on the rows of A. Theorem 2 (Determinants and elementary row operations) Slide 4 Let A be a n×n matrix. • Let B be the result of adding to a row in A a multiple of another row in A. Then, det(B) = det(A). • Let B be the result of interchanging two rows in A. Then, det(B) = −det(A). • Let B be the result of multiply a row in A by a number k. Then, det(B) = kdet(A). ✫ ✪ Math 20F Linear Algebra Lecture 20 3 ✬ ✩ Determinant and elementary row operations Theorem 3 If E represents an elementary row operation and A is an n×n matrix, then det(EA) = det(E)det(A). Slide 5 The proof is to compute the determinant of every elementary row operation matrix, E, and then use the previous theorem. Theorem 4 (Determinant of a product) If A, B are arbitrary n×nmatrices, then det(AB) = det(A)det(B). ✫ ✪ ✬ Determinantofaproduct of matrices ✩ Proof: If A is not invertible, then AB is not invertible, then the theorem holds, because 0 = det(AB) = det(A)det(B) = 0. Suppose that A is invertible. Then there exist elementary row operations Ek,···,E1 such that A=Ek···E1. Slide 6 Then, det(AB) = det(Ek···E1B), = det(Ek)det(Ek−1···E1B), = det(Ek)···det(E1)det(B), = det(Ek···E1)det(B), = det(A)det(B). ✫ ✪ Math 20F Linear Algebra Lecture 20 4 ✬ ✩ Formula for the inverse matrix Slide 7 • Formula for the inverse matrix. • Application to systems of linear equations. ✫ ✪ ✬ ✩ Formula for the inverse matrix Theorem 5 Let A be an n×n matrix with components (A)ij = aij. Let Cij = (−1)i+j det(Aij) be the ijth cofactor, and ∆=det(A). Then the component ij of the inverse matrix A−1 is given by Slide 8 A−1ij = 1 [Cji]. ∆ That is, C11 C21 · · · Cn1 C C · · · C −1 1 12 22 n2 A = . . . . ∆ . . . . . . C1n C2n ··· Cnn ✫ ✪
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