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File: Vector Integration Pdf 171684 | Unit4 Item Download 2023-01-26 22-12-12
unit 4 surface and volume integrals unit 4 surface and how do we calculate the electric field of a spherical charge distribution we volume integrals need to solve a volume ...

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         Unit 4                                                                                              Surface and Volume Integrals 
                                                                                                               
                                     
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                                                                                                              UNIT 4 
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                                                                                       SURFACE AND 
         How do we calculate the electric field 
         of a spherical charge distribution? We                      VOLUME INTEGRALS 
         need to solve a volume integral for 
         this.  
         Structure 
          
         4.1     Introduction                                           4.5     Volume Integrals 
                 Expected Learning Outcomes                                     Volume Integral of the Function f (x, y, z)   
         4.2     Applications of Double Integrals                       4.6     Volume Integral of a Vector Field 
         4.3     Surface Integrals                                      4.7     The Divergence Theorem 
                 Flux of a Vector Field                                         Application of the Divergence Theorem 
                 Flux of a Vector Field as a Surface Integral           4.8     Summary 
                 Surface of Integration                                 4.9     Terminal Questions 
                 Evaluation of Surface Integrals                        4.10    Solutions and Answers 
                 Solid Angle                                             
         4.4     Stokes’ Theorem 
                 Applications of Stokes’ Theorem 
         STUDY GUIDE                                                                                                   
         In this unit, you will study surface integrals and volume integrals. You should study 
          
         Appendix A2 of this block thoroughly before you start studying this unit so that you 
         understand the methods of evaluating double integrals. Surface integrals are evaluated 
         by reducing them to double integrals. Volume integrals are integrations over three 
         variables. Line integrals are used in this unit in the applications of Stokes’ theorem. 
         Therefore, revise how to evaluate line integrals from Unit 3. 
          
             “Everyone now agrees that a physics lacking all connection                                 Franz Karl                     
             with mathematics .... would only be an historical amusement,                               Achard  
             fitter for entertaining the idle, than occupying the mind of a 
             philosopher.”                                                                                  
                                                                                                                              97 
           Block 1                                                                                                                            Vector Analysis 
                                          4.1   INTRODUCTION 
                                          The real world is three-dimensional and as such, most physical functions 
                                          depend on all the three spatial variables (x,y,z), as you have seen in Units 1 
                                          and 2. You have already studied how to integrate vector functions and fields 
                                          with respect to one variable in Unit 3. However, in physics you often have to 
                                          integrate functions of two and three variables, over planes and arbitrary 
                                          surfaces and volumes in space. Such integrals are called multiple integrals. In 
                                          this unit you will study multiple integrals and their applications in physics. You 
                                          will also study two important theorems of vector integral calculus, namely, 
                                          Stokes’ theorem and Gauss’s divergence theorem. 
                                          In Appendix A2 of this block, you have learnt how to evaluate double integrals 
                                          which are integration of functions of two variables and the regions of 
                                          integration are on the coordinate planes. At the beginning of this unit in            
                                          Sec. 4.2, we discuss some applications of double integrals in physics, like 
                                          determining the volume of objects and their centre of mass, etc.  
                                          In Unit 3, you have studied line integrals. Recall that in a line integral, the 
                                          integration is over a single independent variable but the path may be an 
                                          arbitrary curve in space. In Sec. 4.3 of this unit, you will study the surface 
                                          integral of a vector field, in which the integration is over a two-dimensional 
                                          surface in space. Surface integrals are a generalisation of double integrals. 
                                          You will learn how to evaluate a special type of surface integral which is the 
                                          flux of a vector field across a surface. This is used extensively in physics, 
                                          e.g., in electromagnetic theory. You will learn about some other types of 
                                          surface integrals as well. In Sec. 4.4, you will study Stokes’ theorem and its 
                                          applications. Stokes’ theorem tells us how to transform a line integral into a 
                                          surface integral and vice versa. 
                                          In Sec. 4.5, you will learn how to evaluate a volume integral in which the 
                                          integrand is a function of three variables. This is the same as triple integral. In 
                                          Sec. 4.6 you will study Gauss’s divergence theorem and its application. The 
                                          divergence theorem tells us how to transform a surface integral into a volume 
                                          integral and vice versa.   
                                          With this unit we will complete our study of Vector Analysis. In the remaining 
                                          blocks of the course you will study the basic principles of electricity, 
                                          magnetism and electromagnetic theory, where you will use the concepts and 
                                          techniques of vector analysis covered in this block. 
                                          Expected Learning Outcomes 
                                            After studying this unit, you should be able to: 
                                              use double integrals to evaluate physical quantities;  
                                              calculate the flux of a vector field;  
                                              evaluate volume integrals of scalar and vector fields; 
                                              state Stokes’ theorem and Gauss’s divergence  theorem and write them 
                                                in a mathematical form; and 
                                              solve problems based on these theorems and apply them to simple 
            98                                  physical situations. 
             
             Unit 4                                                                                                                     Surface and Volume Integrals 
                                                                                                                                                          
            4.2   APPLICATIONS OF DOUBLE INTEGRALS 
            In Appendix A2 you have studied that a double integral can be used to 
            determine the area of a region and volume of a solid. In the example below, 
            you will use the techniques for evaluating double integrals explained in A2.2 
            and A2.3 to calculate area and volume. 
                    XAMPLE 4.1 : AREA AND VOLUME USING DOUBLE 
                                                   INTEGRALS 
                     
                i)    Determine the area of the region R on xy plane bounded by the curves 
                        y  x  2 and y  x2 by evaluating a double integral. 
                ii)    Calculate the volume of the solid below the surface defined by the 
                       function f(x,y)  4cosx cosy, above the region R on the xy plane 
                       (z = 0), bounded by the curves x  0,x  ,y  0 and y   by 
                       evaluating a double integral. 
                SOLUTION   i)  To determine the area of the region R, we have to 
                evaluate          dxdy where R is the region bounded by the curves y  x 2 
                               
                               R
                and y  x2 (Eq. A2.7). To carry out the double integration we first obtain 
                the limits of integration for the variables x and y in the region R.  
                To obtain the bounds (limits) on x, we solve the system of equations                                                          Note that for y we write  
                y  x2 and y  x 2, to get                                                                                                     2
                                                                                                                                              x y x 2, and not 
                                        x2  x 2x 1,2                                                                                     x  2  y  x2. This is 
                The region of integration R is then defined by the conditions                                                                 because in the range  
                x2  y  x  2, 1 x  2 (read the margin remark) and we write                                                               1x2,, x2  x  2.
                                                            2     x2                   2                                                      
                                                                                              x2
                                                                             
                                                                                             
                                        Area of R                       dy dx              y         dx  
                                                                                               2
                                                           1  x2                     1      x
                                                                             
                                                           2                                  2                3 2
                                                              [x  2 x2] dx x                2x x                9  
                                                                                                                
                                                                                            2                3            2
                                                           1                                                   1
                ii)  The volume of the solid bound by the surface f(x,y)  4cosx cosy 
                     and the region R defined by 0  x  ; 0  y   is (Eq. A2.3) 
                                     
                              V         (4cosxcosy)dydx                                                                (i) 
                                     
                                     00
                     Integrating (i) over y we get: 
                                                                                  
                                      [4y  ycosx siny] dx  [4cosx] dx                                            (ii) 
                                                                      0                                 0
                                     0                                             0                                                                                                        
                     Next, integrating over x, we get 
                                  [4xsinx]                       2
                                                            0 4                                                         (iii) 
                                                                                                                                                                               99 
                Block 1                                                                                                                                                 Vector Analysis 
                                                             
                                                            SAQ 1  -  Determining area and volume using double integrals 
                                                            a)  Calculate the area of the region R bounded by the curves  y  x2 and 
                                                                  y  x3 for x 0; y 0. 
                                                            b)  Find the volume of the solid that lies below the surface of the curve  
                                                                  f(x,y)  x4 and above the region in the xy plane bounded by the curves 
                                                                  y  x2 and y 1. 
                                                            In physics, we also use double integrals to calculate several other quantities. 
                                                            We could use the double integral to determine the mass of an object like a 
                                                            planar lamina with a density function. We can also find the centre of mass of a 
                                                            laminar object or its moment of inertia about an arbitrary axis.  
                                                            Before you solve an example on the applications of double integrals, let us 
                                                            summarize some important applications:  
                                                                             APPLICATIONS OF DOUBLE INTEGRALS 
                                                               
                                                             
                                                                     Centre of mass (x                 ,y      ) of a body with a density (x,y) over a 
                                                                                                    cm cm
                                                                      region R 
                                                                                                       x(x,y)dxdy                              y (x,y)dxdy
                                                                                                                                          
                                                                                       xcm  R                               ; ycm  R                                      (4.1) 
                                                                                                              m                                        m
                                                                     Mass m of a body with a density (mass/area) (x,y)over a region R 
                                                                                       m    (x,y)dxdy                                                                     (4.2) 
                                                                                              
                                                                                               R
                                                                     Moment of inertia of a body with a density(x,y) over a region R 
                                                                      about the x-axis, I  and the y-axis I  
                                                                                                   x                          y
                                                                                       I         y2(x,y)dxdy; I                      x2(x,y)dxdy            (4.3) 
                                                                                        x                                     y
                                                                                                                                   
                                                                                               R                                     R
                                                                     The average value  of a continuous function f(x,y) over a closed 
                                                                      region R in the xy-plane is: 
                                                                            f (x,y)dx dy
                                                                        
                                                                  R                           ;     dxdy  Area of the regionof integration R  (4.4) 
                                                                                 dxdy             
                                                                                                 R
                                                                              R
                                                                
                                                            We study one of these applications in the following example, where we 
                                                            determine the mass of an object using double integrals. 
                                                                   XAMPLE 4.2 :  APPLICATION OF DOUBLE INTEGRAL 
                                                               
                                                                    
                                                               A rectangular plate covers the region 0 x  4;0 y 3 and has the mass 
                                                                    
                100                                            density (x,y) x y. Calculate the mass of the plate. 
                                                                                   
                                                                
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