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picture1_Chemical Kinetics Ncert Pdf 118647 | 2021 06 24 Xii Chemistry 1


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File: Chemical Kinetics Ncert Pdf 118647 | 2021 06 24 Xii Chemistry 1
class xii chemistry chapter 4 chemical kinetics ncert intext questions page no 100 q 4 1 for the reaction r p the concentration of a reactant changes from 0 03 ...

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                                                  Class-XII 
                                                 Chemistry 
                                                 Chapter-4 
                                             Chemical Kinetics 
             NCERT INTEXT QUESTIONS 
             Page No. 100 
             Q.4.1 For the reaction R → P, the concentration of a reactant changes from 
             0.03 M to 0.02 M in 25 minutes. Calculate the average rate of reaction using 
             units of time both in minutes and seconds. 
             Solution: 
                                                                                   
             Q.4.2 In a reaction, 2A → products, the concentration of A decreases from 0.5 
                   -1            -1
             mol L  to 0.4 mol L  in 10 minutes. Calculate the rate during this interval. 
             Solution: 
                                                                          
             Page No. 105 
                                                                                       1/2   2
             Q.4.3 For a reaction, A + B → product; the rate law is given by, r = k[A]    [B] . 
             What is the order of the reaction? 
             Solution: 
                                                                             
                    Q.4.4 The conversion of molecules X to Y follows second order kinetics. If 
                    concentration of X is increased to three times, how will it affect the rate of 
                    formation of Y? 
                    Solution: 
                    The reaction, X → Y, follows second order kinetics hence the rate law equation 
                    will be 
                                   2
                    Rate = kC , where C = [X] 
                                                                                                                      -1
                    If concentration of X increases three times, now, [X] = 3C mol L  
                    ∴ Rate = k(3C) = 9kC  
                                          2         2
                    Thus the rate of reaction will become 9 times. Hence, the rate of formation of 
                    Y will increase 9 times. 
                    Page No. 112 
                                                                                                             -3   -1
                    Q.4.5 A first order reaction has a rate constant 1.15 × 10  s . How long will 5 
                    g of this reactant take to reduce to 3 g? 
                    Solution: 
                                                                                                                      
                    Q.4.6 Time required to decompose SO Cl to half of its initial amount is 60 
                                                                                 2   2 
                    minutes. If the decomposition is a first order reaction, calculate the rate 
                    constant of the reaction. 
                    Solution: 
                                                                                                     
                    Page No.118 
             Q4.7 What will be the effect of temperature on rate constant? 
             Answer: 
             It has been found that for a chemical reaction, with rise in temperature by 10°, 
             the rate constant is nearly doubled. 
             The temperature dependence of the rate of a chemical reaction can be 
             accurately explained by Arrhenius equation. 
                   -Ea/RT
             K = Ae     
             Where A is the Arrhenius factor or the frequency factor. It is also called pre-
             exponential factor. It is a constant specific to a particular reaction. R is gas 
             constant and Ea is activation energy measured in joules/mole (J mol-1). 
             Question 8. 
             The rate of the chemical reaction doubles for an increase of 10 K in absolute 
             temperature from 298 K. Calculate Ea. 
             Solution: 
                                                                               
              
                                                                                 
             Q.4.9 The activation energy for the reaction 2Hl(g) → H2(g) + l2(g) is 209.5 kJ 
                 -1
             mol  at 581 K. Calculate the fraction of molecules of reactants having energy 
             equal to or greater than activation energy. 
             Solution: 
                Fraction of molecules having energy equal to or greater than activation energy 
                is given as 
                                                                                                   
                NCERT EXERCISES: 
                Page No.119 
                4.1 From the rate expression for the following reactions, determine their 
                order of reaction and the dimensions of the rate constants. 
                 (i) 3NO(g) → N O (g) Rate = k[NO]2  
                                    2
                                                   +                     −                      -
                (ii) H O  (aq) + 3I– (aq) + 2H  → 2H O (l) + 3 I Rate = k [H O ] [I ]  
                      2   2                                 2                           2  2
                                                                                  3/2
                (iii) CH CHO (g) → CH  (g) + CO(g) Rate = k [CH CHO]                  
                         3                 4                               3
                 (iv) C H Cl (g) → C H  (g) + HCl (g) Rate = k [C H Cl] 
                       2 5              2 4                              2 5
                Solution: 
                                                                                                 
                                                                                                  
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...Class xii chemistry chapter chemical kinetics ncert intext questions page no q for the reaction r p concentration of a reactant changes from m to in minutes calculate average rate using units time both and seconds solution products decreases mol l during this interval b product law is given by k what order conversion molecules x y follows second if increased three times how will it affect formation hence equation be kc where c increases now thus become increase first has constant s long g take reduce required decompose so cl half its initial amount decomposition effect temperature on answer been found that with rise nearly doubled dependence can accurately explained arrhenius ea rt ae factor or frequency also called pre exponential specific particular gas activation energy measured joules mole j question doubles an absolute hl h kj at fraction reactants having equal greater than as exercises expression following reactions determine their dimensions constants i n o ii aq iii ch cho co i...

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